Question

Solve for x in the equation x^2+2x+1=17​

Answer 1

x= (-1+ √17) or (-1-√17)

Explanation:

In this question, we have to solve for x from the given equation x² +2x+1 =17

Now, the equation can be rearranged to x² +2x -16 =0.

Here we can not apply the process of factorization to get the value of x.

Hence, we will use the Shridhar Acharya formula to solve the value of x.

{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as

x=[-b±√(b²-4ac)]/2a }

Hence, in this case, the solution for x will be

x=
`\frac{-2+\sqrt{2^(2)-4(1)(-16) } }{2(1)} or  \frac{-2-\sqrt{2^(2)-4(1)(-16) } }{2(1)}`

⇒ x=
`(-2+2√(17) )/(2) or  (-2-2√(17) )/(2)`

⇒ x= (-1+ √17) or (-1-√17) (Answer)