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Use contrapositive to prove this. Let x, y ∈ R. If x and y are both positive, then (√ x + y) does not equal √x + √y.

User Nedemir
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Answer:

See explanation

Explanation:

Let x, y ∈ R.

If x and y are both positive, then
√(x+y)\\eq √(x)+√(y)

Suppose that


√(x+y)=√(x)+√(y)

Square both sides of this equation:


(√(x+y))^2=(√(x)+√(y))^2\\ \\x+y=(√(x))^2+2√(x)√(y)+(√(y))^2\\ \\x+y=x+2√(x)√(y)+y\\ \\2√(x)√(y)=0

Then


√(x)=0\ \text{or}\ √(y)=0\\ \\x=0\ \text{or}\ y=0

But x and y are both positive, so the assumption is false

User Mangokun
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