Question

• A cable is suspended over a pulley. A 5.0 kg mass is attached to

one end of a cable and 10.0 kg mass is attached to the other end.
When the system is released, the 5 kg mass accelerates upward.
Find the tension in the cable. Ignore the friction, the mass of the
pulley and the mass of the cable.​

Answer 1

Tension=
`(20g)/(3)` (g=acceleration of gravity)

Step-by-step explanation:

Given that,

A 5Kg and 10Kg are attached by a cable suspended over a pulley.

As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.

So, the equations of motion are

`10g-T = 10a`

`T-5g=5a`

Now adding them we get,

`5g=15a`

`a=(g)/(3)`

Substituting them back in the equation we get,

`10g-10((g)/(3) ) = T`

`T= (20g)/(3)`