Question

A body undergoing a uniformly, acceleraten motion has

two(1s,10ms) and (20s, 48ms) on the velocity time
graph of it motion. The acceleration of the body is?​

Answer 1

`2 m/s^2`

Step-by-step explanation:

The acceleration of an object is given by:

`a=(v-u)/(\Delta t)`

where

v is the final velocity

u is the initial velocity

`\Delta t` is the time interval

For the body in the problem, we have:

`u=10 m/s` at t = 1 s

`v=48 m/s` at t = 20 s

So the time interval is

`\Delta t = 20 -1 = 19 s`

And so, the acceleration is

`a=(48-10)/(19)=2 m/s^2`