Answer:
2 mph
Explanation:
The rate in still water is 6 mph. Let the rate of the water current be x mph.
Downstream:
Distance = 6 miles
Rate = 6 + x mph (current "helps")
t = unknown
![6=(6+x)t\Rightarrow t=(6)/(6+x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ag5a9yjlmsa9rz42yonhi9qyr5mrhfo6ow.png)
Upstream:
Distance = 3 miles
Rate = 6 - x mph (current "interferes")
t = unknown
![3=(6-x)t\Rightarrow t=(3)/(6-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/o6pzcq3wfuj1u6219tsmd9qputs7idz5s7.png)
It takes the same amount of time to travel 6 miles downstream as 3 miles upstream, so
![(6)/(6+x)=(3)/(6-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zr6l8litsdgyo2h9kqhrzkvmbhow3ua1a4.png)
Cross multiply:
![6(6-x)=3(6+x)\\ \\36-6x=18+3x\\ \\36-18=3x+6x\\ \\9x=18\\ \\x=2\ mph](https://img.qammunity.org/2020/formulas/mathematics/high-school/2e918j50hto56n0wfve5whnpr27j0ao0a7.png)