Question

An airplane flies for 1.25 hours with a constant speed of 1080 km/hr and then for another 2.5 hours with a constant speed of 984 km/hr. How far (what distance) did it go?

Answer 1

The airplane went 3810 km

Step-by-step explanation:

The Distance at Constant Speed

The speed is defined as the rate of change of the distance:

`\displaystyle v=(d)/(t)`

The distance is calculated by solving for d:

d = vt

The airplane first flies at v=1080 Km/h for t=1.25 hours. The first distance is:

d1 = 1080 Km/h * 1.25 h = 1350 Km

Then it flies at v=984 Km/h for t=2.5 hours. The second distance is:

d2 = 984 Km/h * 2.5 h = 2460 Km

The total distance was 1350 + 2460 = 3810 km.

The airplane went 3810 km