Question

Find the product of 3 and the linear equation, and solve for both equations for y.

2y-4x=8
The product of 3 and 2y-4x=8 is ______
The original equation in slope intercept form is y=________
The new equation in slope intercept form is______

Answer 1

Part 1) The product of 3 and 2y-4x=8 is
`6y-12x=24`

Part 2) The original equation in slope intercept form is
`y=2x+4`

Part 3) The new equation in slope intercept form is
`y=2x+4`

Explanation:

we have

`2y-4x=8`

step 1

Find out the product of 3 and 2y-4x=8

Multiply both sides by 3

`3(2y-4x)=3(8)`

Apply distributive property both sides

`6y-12x=24`

step 2

Find out the original equation in slope intercept form

The equation of the line in slope intercept form is

`y=mx+b`

we have

`2y-4x=8`

Solve for y

That means ----> Isolate the variable y

Adds 4x both sides

`2y=4x+8`

Divide by 2 both sides

`y=(4x+8)/2`

Simplify

`y=2x+4`

step 3

Find out the new equation in slope intercept form

The equation of the line in slope intercept form is

`y=mx+b`

we have

`6y-12x=24`

Solve for y

That means ----> Isolate the variable y

Adds 12x both sides

`6y=12x+24`

Divide by 6 both sides

`y=(12x+24)/6`

Simplify

`y=2x+4`