Question

A motorcyclist sees a branch in the road,

and hits the brakes, slowing down at
-6.42 m/s2. If it takes him 2.85 s to stop,
what was his starting velocity?
(Unit = m/s)

Answer 1

18.3 m/s

Step-by-step explanation:

Given:

a = -6.42 m/s²

t = 2.85 s

v = 0 m/s

Find: v₀

v = at + v₀

(0 m/s) = (-6.42 m/s²) (2.85 s) + v₀

v₀ = 18.3 m/s