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The lifetime in miles for a certain brand of tire is normally distributed with a mean of 22,000 miles and a standard deviation of 3,100 miles The tire manufacturer wants to offer a money-back guarantee so that no more than 3% of tires will qualify for a refund. What is the minimum number of miles the manufacturer should guarantee that the tires will last?

User Helper
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Answer:

16172

Explanation:


\mu = 22000


\sigma = 3100

We are given that The tire manufacturer wants to offer a money-back guarantee so that no more than 3% of tires will qualify for a refund.

So, P(X≤x)=0.03


P((x-\mu)/(\sigma)\leq (x-22000)/(3100) )=0.03

Refer the z table

So, z corresponding to p value 0.03 is -1.88

So,
z=(x-\mu)/(\sigma)


-1.88=(x-22000)/(3100)


-1.88 * 3100=x-22000


-5828=x-22000


-5828+22000=x


16172=x

Hence the minimum number of miles the manufacturer should guarantee that the tires will last is 16172

User UnsafePointer
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