Question

A strip of copper 370 μm thick and 4.5 mm wide is placed in a uniform magnetic field B with arrow of magnitude 0.30 T, with B with arrow perpendicular to the strip. A current i = 24 A is then sent through the strip such that a Hall potential difference V appears across the width of the strip. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 ✕ 1028 electrons/m3.)

Answer 1

Step-by-step explanation:

The given data is as follows.

Magnetic field (B) = 0.30 T

Current (I) = 24 A

n =
`370 * 10^(-6) m`

charge on electron (e) =
`1.602 * 10^(-19)` C

Formula to calculate the potential difference is as follows.

V =
`(B * I/d)/(n * e )`

=
`(0.30 T * 24 amps)/(8.47 * 10^(28) electrons/ m^(3) * 370 * 10^(-6) m * 1.602 * 10^(-19) C))`

=
`1.38 * 10^(-6)` V

Therefore, we can conclude that value of potential difference is
`1.38 * 10^(-6)` V.