Answer:
ΔH = -201 kJ/mol
Step-by-step explanation:
The Hess' Law say that the enthalpy of one reaction is equal to the sum of all the steps:
C6H12 + 9O2 --> 6CO2 + 6H2O ΔH = -3752 kJ
C6H10 + 17/2O2 --> 6CO2 + 5H2O ΔH = -3953 kJ
C6H10 + H2O --> C6H12 + 1/2O2 ΔH = -3953 + 3752
ΔH = -201 kJ/mol