Question

Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s and was brought jarringly back to rest in only 1.40 s. Calculate his stopping acceleration in multiples of g.

Answer 1

a = 20.532 g

Step-by-step explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

`v=u+at\\\Rightarrow a=(v-u)/(t)\\\Rightarrow a=(0-282)/(1.4)\\\Rightarrow a=-201.42\ m/s^2`

Magnitude of deceleration is 201.42 m/s²

g = 9.81 m/s²

Dividing a by g

`(a)/(g)=(201.42)/(9.81)\\\Rightarrow (a)/(g)=20.532\\\Rightarrow a=20.532g`

a = 20.532 g