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A line contains points M(1, 3) and N(5, 0). What is the slope of MN? negative StartFraction 4 Over 3 EndFraction negative StartFraction 3 Over 4 EndFraction StartFraction 3 Over 4 EndFraction StartFraction 4 Over 3 EndFraction

User Zeno Tsang
by
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2 Answers

2 votes

Answer:

The answer would be option (B) (-3/4)

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User Andrey Gagan
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3 votes

Answer:

The slope would be -3/4

Explanation:

Since, slope of a line having end points
(x_1, y_1) and
(x_2, y_2) is,


m=(y_2-y_1)/(x_2-x_1)

Here, line segment MN contains end points M(1, 3) and N(5, 0)

i.e.


x_1 = 1, y_1 = 3, x_2 = 5, y_2 = 0

Thus, the slope of line MN would be,


m=(0-3)/(5-1)=(-3)/(4)

User Iftikhar Uddin
by
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