Answer:
-68 is not a term in the given sequence
Explanation:
The given sequence is -12, -17, -22, -27...
There is a common difference of d=-17--12=-5
The explicit rule for this sequence is
![f(n)=-12-5(n-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gunrt3gmd1zk315plog3ly95d72zhoi946.png)
Or
![f(n)=-5n-7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7czplaugzwswmfvl24f4zipk9ndwqeggfk.png)
To find the term that has a value of -68 we equate the explicit formula and solve for n.
![-68=-5n-7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5foychnwv8j8qnfr32tpayqfu2coj4tbbo.png)
![\implies -68+7=-5n](https://img.qammunity.org/2020/formulas/mathematics/middle-school/skuvt7gs5de10f3xc4wp989esh7ijv3qmf.png)
![\implies -61=-5n](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h1jgpvfvtxsxjslcntnw2oex1bj7lw43v2.png)
![n=(61)/(5) =12.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2cu6kitu2m8k3c1y4gsziyh0djn0q0tmwl.png)
The position should be a natural number.
Since n is a decimal, it tells us that -68 is not a term in the given sequence