Answer: 0.21
Explanation:
Let A denotes the event that employees are college graduates.
B denotes that the event that employees have more than ten years of experience.
As per given , we have
P(A)=0.51
P(B)=0.47
P(A∪B)=0.77
We know that ,
![P(A\cup B)=P(A)+P(B)-P(A\cap B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hjvmv4ll3g25188919dtl3ycbphwrvckcc.png)
![0.77=0.51+0.47-P(A\cap B)](https://img.qammunity.org/2020/formulas/mathematics/college/ssq6jn1enyyi073vioswgw39kh3h9hu2ed.png)
![P(A\cap B)=0.51+0.47-0.77=0.21](https://img.qammunity.org/2020/formulas/mathematics/college/3few10kd5kvbqs8wxqpprs0iqe8vsjpjj0.png)
Hence, the probability that a randomly selected employee will have more than ten years of experience and be a college graduate = 0.21