Answer:
72 and 73
Explanation:
let the first locker number be "y"
Hence, the next locker number [consecutive] would be "y+1"
Since the SUM is 145, we can add up the two and write and equation. Then simply solve algebraically. Shown below:
![y+y+1=145\\2y+1=145\\2y=145-1\\2y=144\\y=(144)/(2)\\y=72](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wbbldd0cjwitv91pukwws4jq6tueaz9qks.png)
So, the 2 locker numbers are 72 and 73