185k views
4 votes
You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 690.0 kg and was traveling eastward. Car B weighs 520.0 kg and was traveling westward at 74.0 km/h. The cars locked bumpers and slid eastward with their wheels locked for 6.00 m before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750. 1) How fast (in kilometer per hour) was car A traveling just before the collision? (Express your answer to three significant figures.)

User Mdsumner
by
5.1k points

1 Answer

2 votes

Answer:

115 km/h

Step-by-step explanation:


m_1 = Mass of car A = 690 kg


m_2 = Mass of car B = 520 kg

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration

u = Initial velocity

v = Final velocity


a=\mu g\\\Rightarrow a=0.75* 9.81\\\Rightarrow a=7.3575\ m/s^2


v^2-u^2=2as\\\Rightarrow v=√(2as+u^2)\\\Rightarrow v=√(2* 7.3575* 6+0^2)\\\Rightarrow v=9.396\ m/s


m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow u_1=((m_1 + m_2)v-m_2u_2)/(m_1)\\\Rightarrow u_1=((690+520)9.396-520* -(74)/(3.6))/(690)\\\Rightarrow u_1=31.96\ m/s

Converting to km/h


31.96* 3.6=115.056\ km/h

Initial velocity of car A = 115 km/h

User Lakshmi
by
5.2k points