Question

A diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. She starts with a velocity of 4.00 m/s and her takeoff point is 1.80 m above the pool. What is her highest point, in meters, above the board?

Answer 1

0.81549 m

Step-by-step explanation:

t = Time taken by the diver

u = Initial velocity of the diver = 4 m/s

v = Final velocity of the diver

s = Displacement of the diver

a = Acceleration due to gravity = 9.81 m/s²

Equation of motion

`v^2-u^2=2as\\\Rightarrow s=(v^2-u^2)/(2a)\\\Rightarrow s=(0^2-4^2)/(2* -9.81)\\\Rightarrow s=0.81549\ m`

a) Her highest height above the board is 0.81549 m