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how many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? (1 electrons, 2 electrons, 3 electrons, 4 electrons. LiCl, NaF, CaO, BaS, NaBr)​

User Tyb
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2 Answers

7 votes

Answer:

The answer to your question is:

Step-by-step explanation:

Compound Cation Anion Number of electrons

LiCl Li⁺¹ Cl⁻¹ one

NaF Na⁺¹ F⁻¹ one

CaO Ca⁺² O⁻² two

BaS Ba⁺² S⁻² two

NaBr Na⁺¹ Br⁻¹ one

User Anders Abel
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7.7k points
5 votes

Answer:

Step-by-step explanation:

To understand how the answer is gotten, it is recommended to prepare the ionic equation for watch of the compounds and this can be gotten by considering the valency of the atoms.

LiCl;

Li belongs to group 1 so it has a valency of + 1

Cl belongs to group 7 so it has a valency of -1

Ionic equation is given as; Li+ + Cl- -> LiCl

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.

NaF;

Na belongs to group 1 so it has a valency of + 1

F belongs to group 7 so it has a valency of -1

Ionic equation is given as; Na+ + F- -> NaF

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.

CaO;

Ca belongs to group 1 so it has a valency of + 2

Cl belongs to group 6 so it has a valency of -2

Ionic equation is given as; Ca2+ + O2- -> CaO

The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.

BaS;

Ba belongs to group 2 so it has a valency of +2

S belongs to group 6 so it has a valency of -2

Ionic equation is given as; Ba2+ + S2- -> BaS

The number of electrons that are transferred between the cation and anion to form the ionic bond is 2.

NaBr;

Na belongs to group 1 so it has a valency of + 1

Br belongs to group 7 so it has a valency of -1

Ionic equation is given as; Na+ + Br- -> NaBr

The number of electrons that are transferred between the cation and anion to form the ionic bond is 1.

User Dmitry Leskov
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7.8k points