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Through: (-3,0), perp. to y = 3x - 1

1 Answer

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Answer:


y=-(1)/(3)x-1

Explanation:

Given:

line y=3x-1

point (-3,0)

Write: equation of the line that is perpendicular to the given and passes through the point (-3,0)

Solution:

The slope of the given line is
m=3

If
m_1 is the slope of perpendicular line, then


m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-(1)/(3)

So, the equation of the needed line is
y=-(1)/(3)x+b.

Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:


0=-(1)/(3)\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-(1)/(3)x-1