Answer:
![y=-(1)/(3)x-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/upvnp80v2k65j1qlxg0vu7jf38gmsz4dex.png)
Explanation:
Given:
line y=3x-1
point (-3,0)
Write: equation of the line that is perpendicular to the given and passes through the point (-3,0)
Solution:
The slope of the given line is
![m=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2y0cvxapstgefe0revyygfmq28zt6px90j.png)
If
is the slope of perpendicular line, then
![m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/683ghrtmp7nlx1k7qtx8wgvefbkuarunjg.png)
So, the equation of the needed line is
![y=-(1)/(3)x+b.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t0k2paeliei6ehld0m33j6mt8zlbm303ri.png)
Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:
![0=-(1)/(3)\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-(1)/(3)x-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gjrwuq2mu1ae5p5hzd0mbi9jm6n4jgl6ss.png)