Question

7x+4y=5 find the slope of a line parallel and perpendicular

Answer 1

To find the slope of a line parallel, you must firs of all make y the subject of the formula i.e

subtract 7x from both side of the equation

which implies : 7x -7x+4y = 5 - 7x

so, 4y = 5 - 7x

Divide both side by 4, since you are to make y to stand alone

This implies y = 5/4 - 7x/4.

Recall: If M1 represent a slope and M2 represent another slope, if they are parallel , then M1 = M2 and if they are perpendicular, then M1 = -1/M2

SO, the slope parallel = -7/4

And the slope perpendicular = -1 divided by -7/4

which implies -1 x -4/7

= 4/7

Explanation:

Answer 2

Explanation:

7x+4y=5

4Y = -7X +5

y = -7/4x + 5/4

Slope m₁ =-7/4

Slope of the line parallel to this line m₂ = -7/4

Slope (m₃) of the line perpendicular to this line m₃= 4/7

m₁ * m₃ = -1

-7/4 * m₃ = -1

m₃ = -1 * (-4/7) = 4/7