Question

What is the speed of a 48-kilogram dog running across

a lawn with 216 joules of kinetic energy?​

Answer 1

3m/s

Step-by-step explanation:

K.E= (1/2)mv^2

216j= (1/2)48kg • v^2

216J=24kg•v^2

v^2 = (216J)/(24kg)

v^2= 9m^2/s^2

/sqrt{v^2} = /sqrt{9m^2/s^2}

V =3m/s