Question

SinA.secA
__________ = tan²A
cosecA.cosA​

Answer 1

Please check explanations for answer

Explanation:

Here, we want to show that the left hand side equals the right hand side

We can express the left hand side as:

sin A/ cos A * sec A/cosec A

kindly recall that;

sin A/cos A = tan A

Also;

sec A = 1/ cos A

cosec A = 1/ sin A

Thus, we have that ;

tan A * 1/cos A / 1 / sin A

= tan A * sin A/cos A

This is;

tan A * tan A = tan^2 A