Answer:
Explanation:
As we know that
Complex number written as
Z = x + i y
x is the real part (on real axis).
y is the imaginary part(on imaginary axis).
For (1+i)-(1-i):
Z= (1+i)-(1-i)
Z = 1 + i - 1 + i
Z=2 i
So x= 0 ,y= 2
For (1+i)(1-i):
Z= (1+i)(1-i) = 1 - i² ( i² = 1)
Z = 1 - (-1) = 2
So x= 2 and y= 0
For i(2-i)(1+2i):
Z= i(2-i)(1+2i) = (2 i- i²) (1+2i)
Z= (2i + 1) (1+2i)
Z = 2i +1 +4i² + 2i
Z= 4i + 1 - 4
Z= - 3+ 4 i
x = - 3 and y =4