Answer:
11yz² and when evaluating we get 22528
Explanation:
We have the expression
![11\sqrt{y^(2)z^(4) }](https://img.qammunity.org/2020/formulas/mathematics/high-school/4h98p214ltoh0n6evvqy9wsr6laap3fvfj.png)
We know that a square root is a 1/2 exponent, so we're going to multiply the exponents of y and z by 1/2.
![11\sqrt{y^(2)z^(4) }= 11y^(2(1/2))z^(4(1/2)) } =11yz^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rc6jk68fmpn8dlxx0gg7hllqsa5tyhk2x3.png)
Therefore the expression is rewritten as
![11yz^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/7yzq8axglr4ap6o3bi3hzzlryv5rmezfkm.png)
Now we're going to evaluate this expression for y = 8 and z = 16
![11yz^(2) =11(8)(16)^2=88(256)=22528](https://img.qammunity.org/2020/formulas/mathematics/high-school/xfsf5xcg7uhliii6ewfq8985ruftb7fd69.png)
Thus, when evaluated the result is 22528