Answer:
4√2 × 4√8 = 64, an integer.
Explanation:
a) 4√2 × 4√8
First let's remember that a square root can be rewritten as a 1/2 exponent,
Therefore the expression we have can be rewritten as
![4(2^(1/2) )4(8^(1/2))](https://img.qammunity.org/2020/formulas/mathematics/high-school/z2qmo1zt970bsmm8a857hab5h9lph4k970.png)
We are going to write all numbers in their prime factor expressions:
*Note: Remember that when we multiply two numbers with the same base but different exponents we sum up the exponents*
*Also, when we elevate one exponent to another exponent, we multiply the exponents*
![4(2^(1/2) )4(8^(1/2))\\=2^2 (2^(1/2))2^2 (2^(3))^(1/2) \\ =2^2 (2^(1/2))2^2 (2^(3/2))\\=2^22^2(2^(1/2)2^(3/2))\\=16(2^(4/2))\\=16(2^2)\\=16(4)\\=64](https://img.qammunity.org/2020/formulas/mathematics/high-school/o2qqg03speavd93decjygja97gprsak92t.png)
Therefore, the expression 4√2 × 4√8 = 64 and therefore is an integer