Question

Tyiesha says that if the magnitude of a vector u is zero, then u has to be a zero vector. Is she correct? Explain how

Answer 1

Yes ,Tyiesha is correct.

Explanation:

Lets take u vector

u = ai + b j +ck

So the magnitude of vector u given as

`R=√(a^2+b^2+c^2)`

If the magnitude of above vector is zero then the values a= 0 , b= 0 and c=0 should be zero.

a= 0 , b = 0 ,c = 0

So now by putting the values

u = ai + b j +ck

u = 0 i + 0 j +0 k

u = 0 ,u is a zero vector.

It means that u should be zero vector.So Tyiesha is correct.