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38. Write each logarithm as an equivalent expression involving only logarithms base 10.

b. log100(x2)

User Ian Joyce
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1 Answer

3 votes

Answer:


\log_(100)(x^(2)) = (\log_(10)(x^(2)))/(\log_(10)(100)) = (\log_(10)(x^(2)))/(2)

Explanation:

We can use this expression to change the base of a logarithm from b to d.


\log_(b)(x) = (\log_(d)(x))/(\log_(d)(b))

So, to write
\log_(3)(25) as base 10, we can use this formula.


\log_(100)(x^(2)) = (\log_(10)(x^(2)))/(\log_(10)(100)) = (\log_(10)(x^(2)))/(2)

User Dshefman
by
5.5k points
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