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According to the remainder theorem, what is one factor of the cubic expression x³+3x²+x-5?

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Answer:

x - 1

Explanation:

To get one factor of the cubic expression x³+3x²+x-5 according to the remainder theorem we can say that

x³+3x²+x-5 = 0

Then we apply Ruffini's Rule and obtain

x³+3x²+x-5 = (x-1)(x²+4x+5)

where x = 1 is the only real root of the polynomial expression.

User Theheadofabroom
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