Question

What is an equation of the line that is parallel to y=3x−8 and passes through (1, 8) ?

Enter your equation in the box.

Answer 1

The general equation of any line that is parallel to y=3x-8-------------(equation a) is 'y=mx+c'---------------------- (equation 1)

The parallel lines have same slope.

here m describe the slope of the line, while x and y defines the point through which the line has passed. so, taking the point (1,8) here x=1 and y=8 we put the values of the point into the general equation that is eq 1.

We get,

8=m(1)+c solving further we get, 8=m+c-----------(equation b)

Now we need m that is slope to completely solve the equation. We will get 'm' from the line that is parallel to the given line because parallel lines have same slope. so the 'm' of equation a is m is 3. slope is 3 according to the general equation of the line where slope is with x that is 3x in the case of equation a. so putting value of slope into equation b, we will get 8=3+c which is equal to c=12.

so, the equation of the new line that is parallel to equation a will be y=3x+12

Answer 2

y=3x+5

Explanation:

Since the equation will be parallel, the slope will still be 3.

y=3x+b

Enter the point (1,8) into the equation.

8=3(1)+b

8=3+b

b=5

y=3x+5