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Suppose we have a quadratic equation ax²+bx+c=0 so that a+c=0.Does the quadratic equation have one solution or two distinct solutions? Are they real or complex? Explain how you know.

User Roundar
by
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1 Answer

7 votes

Answer:

The roots of equation are real and distinct.

Explanation:

Given that

ax²+bx+c=0

a+c=0

To find the behavior of roots we have to find out D


D=√(b^2-4ac)

If

D> 0 Two real distinct roots

D=0 Two equal roots

D<0 Tow imaginary roots


D=√(b^2-4ac)

a+c=0

a= - c


D=√(b^2-4* (-c)* c)


D=√(b^2+4* c^2)

It means that D>0 .So the roots of equation is real and distinct.

User AsirXing
by
8.5k points
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