Answer:
The roots of equation are real and distinct.
Explanation:
Given that
ax²+bx+c=0
a+c=0
To find the behavior of roots we have to find out D
![D=√(b^2-4ac)](https://img.qammunity.org/2020/formulas/physics/high-school/593zrky58mx4i139f2vciwtoi8hzfiapfu.png)
If
D> 0 Two real distinct roots
D=0 Two equal roots
D<0 Tow imaginary roots
![D=√(b^2-4ac)](https://img.qammunity.org/2020/formulas/physics/high-school/593zrky58mx4i139f2vciwtoi8hzfiapfu.png)
a+c=0
a= - c
![D=√(b^2-4* (-c)* c)](https://img.qammunity.org/2020/formulas/mathematics/high-school/uj81gw9t8jwdoyypyw28hwowq4780d4bxp.png)
![D=√(b^2+4* c^2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/i9g4l9gndxbie9csya7snumuza93x93hot.png)
It means that D>0 .So the roots of equation is real and distinct.