Question

7.Suppose that water is entering a cylindrical water tank so that the initial height of the water is 3 cm and the

height of the water doubles every 30 seconds. Write an equation of the height of the water at time ???????? seconds.

Answer 1

`H(t) = 3*2^(t/30)`

Explanation:

Height doubles at every 30 seconds, so let's call n how many times it happens, and the t the total time:

n = t/30

If the height doubles one time, it is multiplied by 2, if it doubles 2 times, it's multiplied by 2², for n times, it is multiplied by 2ⁿ, so for an initial height equal to 3:

`H(t) = 3*2^(t/30)`