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Find the value of log(4) ∙ log(25) to five decimal places.

User Wlamers
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1 Answer

6 votes

Answer:0.84164

Explanation:

Given


\log \left ( 4\right )\cdot \log \left ( 25\right )

we know


\log a^b=b\log a

Applying this identity we get


\log \left ( 2\right )^2\cdot \log \left ( 5\right )^2


=2\log \left ( 2\right )* 2\log \left ( 5\right )


=4* \log \left ( 2\right )\cdot \left ( 5\right )


=4* 0.301029* 0.698970


=0.84164

User Paqmo
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