Question

Which of the following is the correct order of electron flow in the light reactions of photosynthesis?

a) O2 → P680 chlorophyll a pair → PS I primary electron acceptor → Pq → cytochrome complex → Pc → P700 chlorophyll a pair → PS II primary electron acceptor → Fd → NADPH
b) H2O → P680 chlorophyll a pair → PS II primary electron acceptor → Pq → cytochrome complex → Pc → P700 chlorophyll a pair → PS I primary electron acceptor → Fd → NADPH
c) H2O → P700 chlorophyll a pair → PS I primary electron acceptor → Pc → cytochrome complex → Pq → P680 chlorophyll a pair → PS II primary electron acceptor → Fd → NADPH
d) H2O → P680 chlorophyll a pair → PS II primary electron acceptor → Pq → cytochrome complex → Pc → P700 chlorophyll a pair → PS I primary electron acceptor → Fd → ATP
e) H2O → P680 chlorophyll a pair → PS II primary electron acceptor → Pq → ATP → Pc → P700 chlorophyll a pair → PS I primary electron acceptor → Fd → NADPH

Answer 1

The corect answer is b

Step-by-step explanation:

The process of electron flow in light reaction begins with transfer of electron from H2O to P680,from there the electron is transported to PS 2 primary electron acceptor know as pheophytin,from there the electron is transpoted to plastoquinone,then to cytochrome b6f complex,then to plastocyanine,then to P700,then to A0,then to A1,then to ferridoxin NADP oxidoreductase and in the final step NADP is reduced to NADPH.

This whole process is termed as Z scheme