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Log2(x) + log2(2x) + log2(3x) + log2(36) = 6

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Answer: x = 2/3

Explanation:

log₂(x) + log₂(2x) + log₂(3x) + log₂(36) = 6

According to the following properties of logarithm, we know that:

logₐ(x.y) = logₐ(x) + logₐ(y)

logₐ(x) = n

logₐ(x) = logₐ(y) ⇔ x = y

Applying this properties to the situation:

log₂(x.2x.3x.36) = log₂64

log₂(216x³) = log₂64

216x³ = 64

x³ = 64/216

x³ = 8/27

x = 2/3

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