2 Answers

Charles Brunet · Answer 1 · 2020-10-30T15:28:28+0000

Answer : The frequency of photon is,
and energy of wave is

Explanation : Given,

Wavelength of wave =
699nm=699* 10^(-9)m

First we have to calculate the frequency of wave.

Formula used :

$\\u=(c)/(\lambda)$

where,

$\\u$ = frequency of wave

$\lambda$ = wavelength of wave

c = speed of light =
3* 10^8m/s

Now put all the given values in the above formula, we get:

$\\u=(3* 10^8m/s)/(699* 10^(-9)m)$

$\\u=4.29* 10^(14)s^(-1)=4.29* 10^(14)Hz$
(1Hz=1s^(-1))

The frequency of wave is,
4.29* 10^(14)Hz

Now we have to calculate the energy of wave.

Formula used :

$E=h* \\u$

where,

$\\u$ = frequency of wave

h = Planck's constant =
6.626* 10^(-34)Js

Now put all the given values in the above formula, we get:

E=(6.626* 10^(-34)Js)* (4.29* 10^(14)s^(-1))

E=2.84* 10^(-19)J

Thus, the energy of wave is
2.84* 10^(-19)J

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