Answer:
![y=2x^(2) -1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5fijk7orf3ruwi6tjjeia7dcc6txim5841.png)
Explanation:
For a parabolic equation to NOT contain the point (0,0) it must have a numeric constant independent from both x and y variables, so the general form would be as follows:
![y=2x^(2) +c](https://img.qammunity.org/2020/formulas/mathematics/high-school/tm2a3jj7wfc3b7cwabkydmagf43equs695.png)
Solving the equation for the point (1,1) would give the necessary value for the constant "c" to make the equation valid:
![y=2x^(2) +c\\1=2*(1)^(2) +c\\c = 1 -2 = -1](https://img.qammunity.org/2020/formulas/mathematics/high-school/6l37ankew6vmvjmxrcrapfnmnb8hw5b4qu.png)
Therefore, the equation that meets both of the required conditions is:
![y=2x^(2) -1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5fijk7orf3ruwi6tjjeia7dcc6txim5841.png)