Question

This is confusing :(
Solve the equation x^4-4x^3+6x^2-4x+5=0 is one of its roots is 2-i.

Answer 1

x can be three things: 5, 1, -1

Explanation:

dividend x4 - 4x3 - 6x2 + 4x + 5

- divisor * x3 x4 - 5x3

remainder x3 - 6x2 + 4x + 5

- divisor * x2 x3 - 5x2

remainder - x2 + 4x + 5

- divisor * -x1 - x2 + 5x

remainder - x + 5

- divisor * -x0 - x + 5

remainder 0

Quotient : x3+x2-x-1 Remainder: 0