186k views
5 votes
How many formula units of Nis are contained in a 430. g sample of the compound?

• Use 6.022 x 102 mol 1 for Avogadro's number.
• Report your answer in scientific notation.
• Your answer should have three significant figures​

User Jpierson
by
5.3k points

2 Answers

3 votes

Answer : The number of formula units of NiS contained are,
2.85* 10^(24)

Explanation :

Formula units : It is defined as lowest whole number ratio of ions in an ionic compound.

It is calculate by multiplying the number of moles by Avogadro's number which is
6.022* 10^(23)

We are given:

Mass of given sample = 430 g

Molar mass of NiS = 90.76 g/mole

First we have to calculate the moles of NiS.


\text{Moles of }NiS=\frac{\text{Mass of }NiS}{\text{Molar mass of }NiS}


\text{Moles of }NiS=(430g)/(90.76g/mol)=4.74mole

Now we have to calculate the formula units of NiS.

Number of formula units =
4.74* 6.022* 10^(23)=2.85* 10^(24)

Hence, the number of formula units of NiS contained are,
2.85* 10^(24)

User Sven Erik Knop
by
5.0k points
5 votes

Answer:

2.85x10²⁴ NiS formula units

Step-by-step explanation:

The molar mass of the compound must be calculated first. For that, the molar masses of the atoms that form it are added:

mNiS = mNi + mS = 58.69g + 32.07g = 90.76 g / mol

Now the molar mass can be related to the amount of formula units there will be of the compound. In a mole there are 6,022x10²³ formula units, and we know that it also occupies a mass of 90.76 g, so the mathematical calculation can be performed.

90.76 g NiS _____ 6.022x10²³ formula units

430.0 g NiS _____ X = 2.8531x10²⁴ formula units

Calculation: 430.0 g x 6.022x10²³ x 90.76 g = 2.8531x10²⁴units formula ≅ 2.85x10²⁴

Using scientific notation and using three significant figures to express the result, the answer is that in 430.0g of NiS there are 2.85x1024 formula units of the compound.

User Aaditya Raj
by
5.5k points