Find the coordinates of the three points on the graph of y = (1/2)x² -2x whose x-values are −2, 0, and 4.

asked Feb 13, 2020 234k views

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1 vote

Answer:

y = 6

y = 0

Explanation:

y=(1)/(2)x² -2x

When, x = -2

$y=(1)/(2)* (-2)^2-2*(-2)\\\Rightarrow y=(1)/(2)4+4\\\Rightarrow y=2+4\\\Rightarrow y=6$

y = 6

When, x = 0

$y=(1)/(2)* (0)^2-2*(0)\\\Rightarrow y=0+0\\\Rightarrow y=0$

y = 0

When, x = 4

$y=(1)/(2)* (4)^2-2*(4)\\\Rightarrow y=(1)/(2)16-8\\\Rightarrow y=8-8\\\Rightarrow y=0$

y = 0

Ben Ashton answered Feb 17, 2020

4.4k points

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