Answer:
![\sum_(k=1)^(1000) k](https://img.qammunity.org/2020/formulas/mathematics/high-school/tqvr63r8sdmobcz0chz67b297emu02bh1p.png)
Explanation:
You have to use the summation notation formula:
![\sum_(k)^(n) f(k) = f(1) + f(2) +...+f(n)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4yx18p8bflqg7lmdgpj99a6vn4vwajxgqx.png)
where k is the starting number, n is the ending number and f(k) is the function or the expression to be added.
In this case, you have the sum of the integer numbers from 1 to 1000. Therefore, k=1 and n=1000.
Now, you have to obtain the function f(k) which is the representation of the expression needed to obtain the correct result of the sum.
f(k=1) = 1
f(k=2)=2
f(k=3)=3 ...
You can notice that the value of k corresponds to te value of f(k) therefore f(k) = k
Replacing the values of k, n and f(k) in the formula:
![\sum_(k=1)^(1000) k = 1+2+3+4+...+1000](https://img.qammunity.org/2020/formulas/mathematics/high-school/dajzxhgf938t8cawlzwtpgi9a6gflwwdcs.png)