Question

Write each sum using summation notation.
1+ 3 + 5 + 7 + ⋯ + 99

Answer 1

`\Sigma(2n-1) \left \{ {{n=50} \atop {n=1}} \right. \hspace{5} n\in N`

Explanation:

First, we need to find the sequence associated to the summation. As you can see the sum only takes odd numbers into account. Hence the sequence it is defined by:

`2n-1`

Where:

`n\in N`

Now, we only need to find the limits of the summation:

Evaluating n=1

`2(1)-1=2-1=1`

Evaluating n=50

`2(50)-1=100-1=99`

Therefore the summation can be written as:

`\Sigma(2n-1) \left \{ {{n=50} \atop {n=1}} \right.`