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Bob is pulling a 30kg filing cabinet with a force of 200N , but the filing cabinet refuses to move. The coefficient of static friction between the filing cabinet and the floor is 0.80.

What is the magnitude of the friction force on the filing cabinet?

User NayabSD
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1 Answer

2 votes

Answer:

Magnitude force of friction is 235.2 N

Step-by-step explanation:

The force of friction is the product of weight and the coefficient of static friction

The force have to be bigger than 200N because it don't move

∑F=
F_(n) - F_(fr)


F_(fr) = u*m*g\\F_(fr) = 0.80*30kg*9.8 (m)/(s^(2) ) \\F_(fr) = 235.2 (kg*m)/(s^(2) ) \\F_(fr) = 235.2 } N

The force on the filling cabinet

User McNets
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