Question

Solve √(2x-8) + √(3x-12) = 0.

Answer 1

`x=4`

Explanation:

subtract
`√(3x-12)` from both sides:

`√(2x-8)=-√(3x-12)`

square to both sides:

`(√(2x-8))^(2) =-(√(3x-12))^(2) \\2x-8=-(3x-12)`

Add 3x-12 to both sides:

`2x-8+3x-12=0\\5x-20=0`

Add 20to both sides:

`5x=20`

Finally, Divide both sides by 5:

`x=(20)/(5)=4`