Question

Circle all the ordered pairs (x,y) that are solutions to the equation 4x−y=10.

(3,2) (2,3) (−1,−14) (0,0) (1,−6)
(5,10) (0,−10) (3,4) (6,0) (4,−1)

Answer 1

Explanation:

given,

equation 4 x−y=10-----(1)

to be the solution of the ordered pair should satisfy

putting(3,2)

4(3) - 2 = 10 hence (3,2) is the solution of the equation

putting(2,3)

4(2) - 3 = 5 hence (2,3) is not the solution of the equation

putting (−1,−14)

4(-1) - (-14) = 10 hence (−1,−14) is the solution of the equation

putting (0,0)

4(0) - (0) = 0 hence (0,0) is not the solution of the equation.

putting (1,−6)

4(1) - (-6) = 10 hence (1,−6) is the solution of the equation.

putting (5,10)

4(5) - (10) = 10 hence (5,10) is the solution of the equation.

putting (0,−10)

4(0) - (-10) = 10 hence (0,−10) is the solution of the equation.

putting (3,4)

4(3) - (4) = 8 hence (3,4) is not the solution of the equation.

putting (6,0)

4(6) - (0) = 24 hence (6,0) is not the solution of the equation.

putting (4,-1)

4(4) - (-1) = 17 hence (4,−1) is not the solution of the equation.

now, circle order pairs is in the image attached below