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Find the difference between the terms a10 of an arithmetic sequence and a geometric sequence, both of which

begin at term a0 and have a2 = 4 and a4 = 12.

1 Answer

3 votes

Answer:-288

Explanation:

Given

First term
a_0 is common for both AP and GP

For AP


a_2=4=a_0+2d---1


a_4=12=a_0+4d----2

From 1 & 2 we get

d=4


a_0=-4


a_(10) for AP


a_(10)=a_0+10d=-4+10* 4=36

For GP


4=a_0r^2----3


12=a_0r^4----4

From 3 & 4 we get


3=r^2


r=√(3)


a_0=(4)/(3)

For
a_(10)=(4)/(3)* 3^5=324


AP_{a_(10)}-GP_{a_(10)}=36-324=-288

User Vinnie Fusca
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