Question

Solve the following systems of equations.
2^(2x+y−1) = 32
4^(x−2y) = 2

Answer 1

Answer:(x,y)=(2.5,1)

Explanation:

Given

`2^(2x+y-1)=32`

`2^(2x+y-1)=2^5`

thus on comparing

2x+y=6------1

`4^(x-2y)=2`

`2^(2(x-2y))=2`

On comparing exponent of 2

`x-2y=(1)/(2)` ------2

we get x=2.5

substitute x in 1

y=1

(x,y)=(2.5,1)