Question

A 161-kg block is pulled at a constant speed of 7.40 m/s across a horizontal floor by an applied force of 138 N directed 36° above the horizontal. What is the rate at which the force does work on the block?

Answer 1

510.6 W

Step-by-step explanation:

The rate at which the force does work is called power therefore it is given by:

`P=(\Delta W)/(\Delta t)`

The instantaneous power applied on a rigid solid is given by the product of the constant force applied over the solid's velocity.

`P=F\cdot v\\P=Fvcos\theta`

Here
`\theta` is the angle between the force and the velocity.

`P=138N(7.4(m)/(s))cos(36^\circ)\\P=510.6W`