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28 votes
28 votes
50 pts please help me and explain

50 pts please help me and explain-example-1
User KMC
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3.0k points

2 Answers

28 votes
28 votes

Answer:

3 adult tickets and 4 kid tickets

Explanation:

So, with an equation like this, if you know how many of one of the types of tickets a person bought, then we can make an equation and find out how many of the other kind they bought.

But, since we don't know how many of either type of ticket was purchased, we can basically guess different combinations of the amount of each of the tickets.

We know there are 7 total tickets purchased, with a total price of $72. We also know the price of both adult tickets ($12) and student tickets ($9).

So, with that information, we can make an equation where a represents the number of adult tickets and k represents the total amount of kid tickets.

12a + 9k = 72

Now, let's guess combinations of amounts of each kind of ticket.

let's try 4 adult tickets and 3 kid tickets.

12(4) + 9(3) = 75

Well, 75 is close to 72, so let's try a similar combination.

Let's do the opposite this time. 3 adult tickets and 4 kid tickets.

12(3) + 9(4) = 72

Well, there we go. Just try and make some educated guesses.

User Bei
by
3.0k points
20 votes
20 votes

Answer:

3 adults and 4 kids

Explanation:

I just went through process of elimination of different possibilities like 2 adults and 5 kids, etc.

Then when I got the right answer all I did was multiply.

adults.) 12 x 3 = $36

kids.) 9 x 4 = $36

Then add both amounts.

$36 + $36 = $72

User Marlon Dias
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3.4k points