Question

A triply charged ion with velocity 7.00 × 10^6 m/s moves in a path of radius 36.0 cm in a magnetic field of 0.55 T in a mass spectrometer. What is the mass of this ion?

Answer 1

Mass of ion will be
`22* 10^(-13)kg`

Step-by-step explanation:

We have given ion is triply charged that is
`q=3* 1.6* 10^(-19)=4.8* 10^(-19)C`

Radius r = 36 cm = 0.36 m

Velocity of the electron
`v=7* 10^6m/sec`

Magnetic field B = 0.55 T

We know that radius of the path is given by
`r=(mv)/(qB)`

`m=(rqB)/(v)=(0.36* 4.8* 10^(-19)* 7* 10^6)/(0.55)=22* 10^(-13)kg`